Solve 10j(2x+55^circ)=1050^circ

$$10 j ( 2 x + 55 ^ { \circ } ) = 1050 ^ { \circ }$$

Solve for j

$$j=\frac{105}{2x+55}$$

$$x\neq -\frac{55}{2}$$

Steps for Solving Linear Equation

Use the distributive property to multiply 10j by 2x+55.

$$20jx+550j=1050$$

Combine all terms containing j.

$$\left(20x+550\right)j=1050$$

Divide both sides by 20x+550.

$$\frac{\left(20x+550\right)j}{20x+550}=\frac{1050}{20x+550}$$

Dividing by 20x+550 undoes the multiplication by 20x+550.

$$j=\frac{1050}{20x+550}$$

Divide 1050 by 20x+550.

$$j=\frac{105}{2x+55}$$

Solve for x

$$x=-\frac{55}{2}+\frac{105}{2j}$$

$$j\neq 0$$

Steps for Solving Linear Equation

Use the distributive property to multiply 10j by 2x+55.

$$20xj+550j=1050$$

Subtract 550j from both sides.

$$20xj=1050-550j$$

The equation is in standard form.

$$20jx=1050-550j$$

Divide both sides by 20j.

$$\frac{20jx}{20j}=\frac{1050-550j}{20j}$$

Dividing by 20j undoes the multiplication by 20j.

$$x=\frac{1050-550j}{20j}$$

Divide 1050-550j by 20j.

$$x=-\frac{55}{2}+\frac{105}{2j}$$