Solve 10c+3p+0.5H=100

$$10 c + 3 p + 0.5 H = 100$$

Solve for H

$$H=200-20c-6p$$

Steps for Solving Linear Equation

Subtract 10c from both sides.

$$3p+0.5H=100-10c$$

Subtract 3p from both sides.

$$0.5H=100-10c-3p$$

Multiply both sides by 2.

$$\frac{0.5H}{0.5}=\frac{100-10c-3p}{0.5}$$

Dividing by 0.5 undoes the multiplication by 0.5.

$$H=\frac{100-10c-3p}{0.5}$$

Divide 100-10c-3p by 0.5 by multiplying 100-10c-3p by the reciprocal of 0.5.

$$H=200-20c-6p$$

Solve for c

$$c=-\frac{H}{20}-\frac{3p}{10}+10$$

Steps for Solving Linear Equation

Subtract 3p from both sides.

$$10c+0.5H=100-3p$$

Subtract 0.5H from both sides.

$$10c=100-3p-0.5H$$

The equation is in standard form.

$$10c=-\frac{H}{2}-3p+100$$

Divide both sides by 10.

$$\frac{10c}{10}=\frac{-\frac{H}{2}-3p+100}{10}$$

Dividing by 10 undoes the multiplication by 10.

$$c=\frac{-\frac{H}{2}-3p+100}{10}$$

Divide 100-3p-\frac{H}{2} by 10.

$$c=-\frac{H}{20}-\frac{3p}{10}+10$$