Solve 10-3(2-5x)^2

$$10 - 3 ( 2 - 5 x ) ^ { 2 }$$

Evaluate

$$-3\left(2-5x\right)^{2}+10$$

Solution Steps

Use binomial theorem \left(a-b\right)^{2}=a^{2}-2ab+b^{2} to expand \left(2-5x\right)^{2}.

$$10-3\left(4-20x+25x^{2}\right)$$

Use the distributive property to multiply -3 by 4-20x+25x^{2}.

$$10-12+60x-75x^{2}$$

Subtract 12 from 10 to get -2.

$$-2+60x-75x^{2}$$

Expand

$$-75x^{2}+60x-2$$

Solution Steps

Use binomial theorem \left(a-b\right)^{2}=a^{2}-2ab+b^{2} to expand \left(2-5x\right)^{2}.

$$10-3\left(4-20x+25x^{2}\right)$$

Use the distributive property to multiply -3 by 4-20x+25x^{2}.

$$10-12+60x-75x^{2}$$

Subtract 12 from 10 to get -2.

$$-2+60x-75x^{2}$$