Solve 10-(-2-1+5*3)*[-4+1*(-1)]+8+4*(-2)=

$$10 - ( - 2 - 1 + 5 \cdot 3 ) \cdot [ - 4 + 1 \cdot ( - 1 ) ] + 8 + 4 \cdot ( - 2 ) =$$

Evaluate

$$70$$

Solution Steps

Subtract 1 from -2 to get -3.

$$10-\left(-3+5\times 3\right)\left(-4+1\left(-1\right)\right)+8+4\left(-2\right)$$

Multiply 5 and 3 to get 15.

$$10-\left(-3+15\right)\left(-4+1\left(-1\right)\right)+8+4\left(-2\right)$$

Add -3 and 15 to get 12.

$$10-12\left(-4+1\left(-1\right)\right)+8+4\left(-2\right)$$

Multiply 1 and -1 to get -1.

$$10-12\left(-4-1\right)+8+4\left(-2\right)$$

Subtract 1 from -4 to get -5.

$$10-12\left(-5\right)+8+4\left(-2\right)$$

Multiply 12 and -5 to get -60.

$$10-\left(-60\right)+8+4\left(-2\right)$$

The opposite of -60 is 60.

$$10+60+8+4\left(-2\right)$$

Add 10 and 60 to get 70.

$$70+8+4\left(-2\right)$$

Add 70 and 8 to get 78.

$$78+4\left(-2\right)$$

Multiply 4 and -2 to get -8.

$$78-8$$

Subtract 8 from 78 to get 70.

$$70$$

Factor

$$2\times 5\times 7$$