Solve 10(x+8)^2-5=-815

$$10 ( x + 8 ) ^ { 2 } - 5 = - 815$$

Solve for x (complex solution)

$$x=-8-9i$$

$$x=-8+9i$$

Steps by Finding Square Root

Subtracting 5 from itself leaves 0.

$$10\left(x+8\right)^{2}=-815+5$$

Add -815 to 5.

$$10\left(x+8\right)^{2}=-810$$

Divide both sides by 10.

$$\frac{10\left(x+8\right)^{2}}{10}=-\frac{810}{10}$$

Dividing by 10 undoes the multiplication by 10.

$$\left(x+8\right)^{2}=-\frac{810}{10}$$

Divide -810 by 10.

$$\left(x+8\right)^{2}=-81$$

Take the square root of both sides of the equation.

$$x+8=9i x+8=-9i$$

Subtract 8 from both sides of the equation.

$$x+8-8=9i-8 x+8-8=-9i-8$$

Subtracting 8 from itself leaves 0.

$$x=9i-8 x=-9i-8$$

Subtract 8 from 9i.

$$x=-8+9i$$

Subtract 8 from -9i.

$$x=-8-9i$$

The equation is now solved.

$$x=-8+9i x=-8-9i$$