Solve 10x^1+20y^2=30^

$$10 { x }^{ 1 } +20 { y }^{ 2 } = { 30 }^{ }$$

Solve for x

$$x=3-2y^{2}$$

Steps for Solving Linear Equation

Calculate x to the power of 1 and get x.

$$10x+20y^{2}=30^{1}$$

Calculate 30 to the power of 1 and get 30.

$$10x+20y^{2}=30$$

Subtract 20y^{2} from both sides.

$$10x=30-20y^{2}$$

Divide both sides by 10.

$$\frac{10x}{10}=\frac{30-20y^{2}}{10}$$

Dividing by 10 undoes the multiplication by 10.

$$x=\frac{30-20y^{2}}{10}$$

Divide 30-20y^{2} by 10.

$$x=3-2y^{2}$$

Solve for y (complex solution)

$$y=-\frac{\sqrt{6-2x}}{2}$$

$$y=\frac{\sqrt{6-2x}}{2}$$

Solve for y

$$y=\frac{\sqrt{6-2x}}{2}$$

$$y=-\frac{\sqrt{6-2x}}{2}\text{, }x\leq 3$$