Solve 10*0-(7*0-(4*0-(3*0-5)))=10*0-(7*0-(4*0+(3*0-5)))

$$10 \times 0-(7 \times 0-(4 \times 0-(3 \times 0-5)))=10 \times 0-(7 \times 0-(4 \times 0+(3 \times 0-5)))$$

Verify

Solution Steps

Multiply 10 and 0 to get 0.

$$0-\left(7\times 0-\left(4\times 0-\left(3\times 0-5\right)\right)\right)=10\times 0-\left(7\times 0-\left(4\times 0+3\times 0-5\right)\right)$$

Multiply 7 and 0 to get 0.

$$0-\left(0-\left(4\times 0-\left(3\times 0-5\right)\right)\right)=10\times 0-\left(7\times 0-\left(4\times 0+3\times 0-5\right)\right)$$

Multiply 4 and 0 to get 0.

$$0-\left(0-\left(0-\left(3\times 0-5\right)\right)\right)=10\times 0-\left(7\times 0-\left(4\times 0+3\times 0-5\right)\right)$$

Multiply 3 and 0 to get 0.

$$0-\left(0-\left(0-\left(0-5\right)\right)\right)=10\times 0-\left(7\times 0-\left(4\times 0+3\times 0-5\right)\right)$$

Subtract 5 from 0 to get -5.

$$0-\left(0-\left(0-\left(-5\right)\right)\right)=10\times 0-\left(7\times 0-\left(4\times 0+3\times 0-5\right)\right)$$

The opposite of -5 is 5.

$$0-\left(0-\left(0+5\right)\right)=10\times 0-\left(7\times 0-\left(4\times 0+3\times 0-5\right)\right)$$

Add 0 and 5 to get 5.

$$0-\left(0-5\right)=10\times 0-\left(7\times 0-\left(4\times 0+3\times 0-5\right)\right)$$

Subtract 5 from 0 to get -5.

$$0-\left(-5\right)=10\times 0-\left(7\times 0-\left(4\times 0+3\times 0-5\right)\right)$$

The opposite of -5 is 5.

$$0+5=10\times 0-\left(7\times 0-\left(4\times 0+3\times 0-5\right)\right)$$

Add 0 and 5 to get 5.

$$5=10\times 0-\left(7\times 0-\left(4\times 0+3\times 0-5\right)\right)$$

Multiply 10 and 0 to get 0.

$$5=0-\left(7\times 0-\left(4\times 0+3\times 0-5\right)\right)$$

Multiply 7 and 0 to get 0.

$$5=0-\left(0-\left(4\times 0+3\times 0-5\right)\right)$$

Multiply 4 and 0 to get 0. Multiply 3 and 0 to get 0.

$$5=0-\left(0-\left(0+0-5\right)\right)$$

Add 0 and 0 to get 0.

$$5=0-\left(0-\left(-5\right)\right)$$

The opposite of -5 is 5.

$$5=0-\left(0+5\right)$$

Add 0 and 5 to get 5.

$$5=0-5$$

Subtract 5 from 0 to get -5.

$$5=-5$$

Compare 5 and -5.

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