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x+\frac{1}{3}=\frac{\frac{1}{4}}{10}
Divide both sides by 10.
x+\frac{1}{3}=\frac{1}{4\times 10}
Express \frac{\frac{1}{4}}{10} as a single fraction.
x+\frac{1}{3}=\frac{1}{40}
Multiply 4 and 10 to get 40.
x=\frac{1}{40}-\frac{1}{3}
Subtract \frac{1}{3} from both sides.
x=\frac{3}{120}-\frac{40}{120}
Least common multiple of 40 and 3 is 120. Convert \frac{1}{40} and \frac{1}{3} to fractions with denominator 120.
x=\frac{3-40}{120}
Since \frac{3}{120} and \frac{40}{120} have the same denominator, subtract them by subtracting their numerators.
x=-\frac{37}{120}
Subtract 40 from 3 to get -37.