Solve 101/4div(21/2+6)

$$10 \frac { 1 } { 4 } \div ( 2 \frac { 1 } { 2 } + 6 )$$

Evaluate

$$\frac{41}{34}\approx 1.205882353$$

Solution Steps

Multiply 10 and 4 to get 40.

$$\frac{\frac{40+1}{4}}{\frac{2\times 2+1}{2}+6}$$

Add 40 and 1 to get 41.

$$\frac{\frac{41}{4}}{\frac{2\times 2+1}{2}+6}$$

Multiply 2 and 2 to get 4.

$$\frac{\frac{41}{4}}{\frac{4+1}{2}+6}$$

Add 4 and 1 to get 5.

$$\frac{\frac{41}{4}}{\frac{5}{2}+6}$$

Convert 6 to fraction \frac{12}{2}.

$$\frac{\frac{41}{4}}{\frac{5}{2}+\frac{12}{2}}$$

Since \frac{5}{2} and \frac{12}{2} have the same denominator, add them by adding their numerators.

$$\frac{\frac{41}{4}}{\frac{5+12}{2}}$$

Add 5 and 12 to get 17.

$$\frac{\frac{41}{4}}{\frac{17}{2}}$$

Divide \frac{41}{4} by \frac{17}{2} by multiplying \frac{41}{4} by the reciprocal of \frac{17}{2}.

$$\frac{41}{4}\times \frac{2}{17}$$

Multiply \frac{41}{4} times \frac{2}{17} by multiplying numerator times numerator and denominator times denominator.

$$\frac{41\times 2}{4\times 17}$$

Do the multiplications in the fraction \frac{41\times 2}{4\times 17}.

$$\frac{82}{68}$$

Reduce the fraction \frac{82}{68} to lowest terms by extracting and canceling out 2.

$$\frac{41}{34}$$

Factor

$$\frac{41}{2 \cdot 17} = 1\frac{7}{34} = 1.2058823529411764$$