Solve 10^3+(1/30)^-2-(-3)^3*0.3^-1+12

$$10 ^ { 3 } + ( \frac { 1 } { 30 } ) ^ { - 2 } - ( - 3 ) ^ { 3 } \times 0.3 ^ { - 1 } + 12$$

Evaluate

$$2002$$

Solution Steps

Calculate 10 to the power of 3 and get 1000.

$$1000+\left(\frac{1}{30}\right)^{-2}-\left(-3\right)^{3}\times 0.3^{-1}+12$$

Calculate \frac{1}{30} to the power of -2 and get 900.

$$1000+900-\left(-3\right)^{3}\times 0.3^{-1}+12$$

Add 1000 and 900 to get 1900.

$$1900-\left(-3\right)^{3}\times 0.3^{-1}+12$$

Calculate -3 to the power of 3 and get -27.

$$1900-\left(-27\times 0.3^{-1}\right)+12$$

Calculate 0.3 to the power of -1 and get \frac{10}{3}.

$$1900-\left(-27\times \frac{10}{3}\right)+12$$

Multiply -27 and \frac{10}{3} to get -90.

$$1900-\left(-90\right)+12$$

The opposite of -90 is 90.

$$1900+90+12$$

Add 1900 and 90 to get 1990.

$$1990+12$$

Add 1990 and 12 to get 2002.

$$2002$$

Factor

$$2\times 7\times 11\times 13$$