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100=2x^{2}+x^{2}
Calculate 10 to the power of 2 and get 100.
100=3x^{2}
Combine 2x^{2} and x^{2} to get 3x^{2}.
3x^{2}=100
Swap sides so that all variable terms are on the left hand side.
x^{2}=\frac{100}{3}
Divide both sides by 3.
x=\frac{10\sqrt{3}}{3} x=-\frac{10\sqrt{3}}{3}
Take the square root of both sides of the equation.
100=2x^{2}+x^{2}
Calculate 10 to the power of 2 and get 100.
100=3x^{2}
Combine 2x^{2} and x^{2} to get 3x^{2}.
3x^{2}=100
Swap sides so that all variable terms are on the left hand side.
3x^{2}-100=0
Subtract 100 from both sides.
x=\frac{0±\sqrt{0^{2}-4\times 3\left(-100\right)}}{2\times 3}
This equation is in standard form: ax^{2}+bx+c=0. Substitute 3 for a, 0 for b, and -100 for c in the quadratic formula, \frac{-b±\sqrt{b^{2}-4ac}}{2a}.
x=\frac{0±\sqrt{-4\times 3\left(-100\right)}}{2\times 3}
Square 0.
x=\frac{0±\sqrt{-12\left(-100\right)}}{2\times 3}
Multiply -4 times 3.
x=\frac{0±\sqrt{1200}}{2\times 3}
Multiply -12 times -100.
x=\frac{0±20\sqrt{3}}{2\times 3}
Take the square root of 1200.
x=\frac{0±20\sqrt{3}}{6}
Multiply 2 times 3.
x=\frac{10\sqrt{3}}{3}
Now solve the equation x=\frac{0±20\sqrt{3}}{6} when ± is plus.
x=-\frac{10\sqrt{3}}{3}
Now solve the equation x=\frac{0±20\sqrt{3}}{6} when ± is minus.
x=\frac{10\sqrt{3}}{3} x=-\frac{10\sqrt{3}}{3}
The equation is now solved.