Solve 10^-2*1+10^3div10^5

$$10 ^ { - 2 } \times 1 + 10 ^ { 3 } \div 10 ^ { 5 }$$

Evaluate

$$\frac{1}{50}=0.02$$

Solution Steps

Rewrite 10^{5} as 10^{3}\times 10^{2}. Cancel out 10^{3} in both numerator and denominator.

$$10^{-2}\times 1+\frac{1}{10^{2}}$$

Calculate 10 to the power of -2 and get \frac{1}{100}.

$$\frac{1}{100}\times 1+\frac{1}{10^{2}}$$

Multiply \frac{1}{100} and 1 to get \frac{1}{100}.

$$\frac{1}{100}+\frac{1}{10^{2}}$$

Calculate 10 to the power of 2 and get 100.

$$\frac{1}{100}+\frac{1}{100}$$

Add \frac{1}{100} and \frac{1}{100} to get \frac{1}{50}.

$$\frac{1}{50}$$

Factor

$$\frac{1}{2 \cdot 5 ^ {2}} = 0.02$$