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Solve for x
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Solve for x (complex solution)
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100^{8-5x}=10
Swap sides so that all variable terms are on the left hand side.
100^{-5x+8}=10
Use the rules of exponents and logarithms to solve the equation.
\log(100^{-5x+8})=\log(10)
Take the logarithm of both sides of the equation.
\left(-5x+8\right)\log(100)=\log(10)
The logarithm of a number raised to a power is the power times the logarithm of the number.
-5x+8=\frac{\log(10)}{\log(100)}
Divide both sides by \log(100).
-5x+8=\log_{100}\left(10\right)
By the change-of-base formula \frac{\log(a)}{\log(b)}=\log_{b}\left(a\right).
-5x=\frac{1}{2}-8
Subtract 8 from both sides of the equation.
x=-\frac{\frac{15}{2}}{-5}
Divide both sides by -5.