Solve for b
b=\frac{19-c}{3}
Solve for c
c=19-3b
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-9+3b+c=10
Swap sides so that all variable terms are on the left hand side.
3b+c=10+9
Add 9 to both sides.
3b+c=19
Add 10 and 9 to get 19.
3b=19-c
Subtract c from both sides.
\frac{3b}{3}=\frac{19-c}{3}
Divide both sides by 3.
b=\frac{19-c}{3}
Dividing by 3 undoes the multiplication by 3.
-9+3b+c=10
Swap sides so that all variable terms are on the left hand side.
3b+c=10+9
Add 9 to both sides.
3b+c=19
Add 10 and 9 to get 19.
c=19-3b
Subtract 3b from both sides.
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