Solve 10=p^2-10/2

$$10 = \frac { p ^ { 2 } - 10 } { 2 }$$

Solve for p

$$p=\sqrt{30}\approx 5.477225575$$

$$p=-\sqrt{30}\approx -5.477225575$$

Steps by Finding Square Root

Multiply both sides by 2.

$$10\times 2=p^{2}-10$$

Multiply 10 and 2 to get 20.

$$20=p^{2}-10$$

Swap sides so that all variable terms are on the left hand side.

$$p^{2}-10=20$$

Add 10 to both sides.

$$p^{2}=20+10$$

Add 20 and 10 to get 30.

$$p^{2}=30$$

Take the square root of both sides of the equation.

$$p=\sqrt{30} p=-\sqrt{30}$$

Steps Using the Quadratic Formula

Multiply both sides by 2.

$$10\times 2=p^{2}-10$$

Multiply 10 and 2 to get 20.

$$20=p^{2}-10$$

Swap sides so that all variable terms are on the left hand side.

$$p^{2}-10=20$$

Subtract 20 from both sides.

$$p^{2}-10-20=0$$

Subtract 20 from -10 to get -30.

$$p^{2}-30=0$$

This equation is in standard form: ax^{2}+bx+c=0. Substitute 1 for a, 0 for b, and -30 for c in the quadratic formula, \frac{-b±\sqrt{b^{2}-4ac}}{2a}.

$$p=\frac{0±\sqrt{0^{2}-4\left(-30\right)}}{2}$$

Square 0.

$$p=\frac{0±\sqrt{-4\left(-30\right)}}{2}$$

Multiply -4 times -30.

$$p=\frac{0±\sqrt{120}}{2}$$

Take the square root of 120.

$$p=\frac{0±2\sqrt{30}}{2}$$

Now solve the equation p=\frac{0±2\sqrt{30}}{2} when ± is plus.

$$p=\sqrt{30}$$

Now solve the equation p=\frac{0±2\sqrt{30}}{2} when ± is minus.

$$p=-\sqrt{30}$$

The equation is now solved.

$$p=\sqrt{30} p=-\sqrt{30}$$