Solve 10+(-10)*2^2-(-5)^5+(-8)*(-1)^5-(-2)^6

$$10 + ( - 10 ) \cdot 2 ^ { 2 } - ( - 5 ) ^ { 5 } + ( - 8 ) \cdot ( - 1 ) ^ { 5 } - ( - 2 ) ^ { 6 }$$

Evaluate

$$3039$$

Solution Steps

Calculate 2 to the power of 2 and get 4.

$$10-10\times 4-\left(-5\right)^{5}-8\left(-1\right)^{5}-\left(-2\right)^{6}$$

Multiply -10 and 4 to get -40.

$$10-40-\left(-5\right)^{5}-8\left(-1\right)^{5}-\left(-2\right)^{6}$$

Subtract 40 from 10 to get -30.

$$-30-\left(-5\right)^{5}-8\left(-1\right)^{5}-\left(-2\right)^{6}$$

Calculate -5 to the power of 5 and get -3125.

$$-30-\left(-3125\right)-8\left(-1\right)^{5}-\left(-2\right)^{6}$$

The opposite of -3125 is 3125.

$$-30+3125-8\left(-1\right)^{5}-\left(-2\right)^{6}$$

Add -30 and 3125 to get 3095.

$$3095-8\left(-1\right)^{5}-\left(-2\right)^{6}$$

Calculate -1 to the power of 5 and get -1.

$$3095-8\left(-1\right)-\left(-2\right)^{6}$$

Multiply -8 and -1 to get 8.

$$3095+8-\left(-2\right)^{6}$$

Add 3095 and 8 to get 3103.

$$3103-\left(-2\right)^{6}$$

Calculate -2 to the power of 6 and get 64.

$$3103-64$$

Subtract 64 from 3103 to get 3039.

$$3039$$

Factor

$$3\times 1013$$