Solve 1.70+(7-6/7-6+7+1)(.05)

$$1.70 + ( \frac { 7 - 6 } { 7 - 6 + 7 + 1 } ) ( .05 )$$

Evaluate

$$\frac{307}{180}\approx 1.705555556$$

Solution Steps

Subtract 6 from 7 to get 1.

$$1.7+\frac{1}{7-6+7+1}\times 0.05$$

Subtract 6 from 7 to get 1.

$$1.7+\frac{1}{1+7+1}\times 0.05$$

Add 1 and 7 to get 8.

$$1.7+\frac{1}{8+1}\times 0.05$$

Add 8 and 1 to get 9.

$$1.7+\frac{1}{9}\times 0.05$$

Convert decimal number 0.05 to fraction \frac{5}{100}. Reduce the fraction \frac{5}{100} to lowest terms by extracting and canceling out 5.

$$1.7+\frac{1}{9}\times \frac{1}{20}$$

Multiply \frac{1}{9} times \frac{1}{20} by multiplying numerator times numerator and denominator times denominator.

$$1.7+\frac{1\times 1}{9\times 20}$$

Do the multiplications in the fraction \frac{1\times 1}{9\times 20}.

$$1.7+\frac{1}{180}$$

Convert decimal number 1.7 to fraction \frac{17}{10}.

$$\frac{17}{10}+\frac{1}{180}$$

Least common multiple of 10 and 180 is 180. Convert \frac{17}{10} and \frac{1}{180} to fractions with denominator 180.

$$\frac{306}{180}+\frac{1}{180}$$

Since \frac{306}{180} and \frac{1}{180} have the same denominator, add them by adding their numerators.

$$\frac{306+1}{180}$$

Add 306 and 1 to get 307.

$$\frac{307}{180}$$

Factor

$$\frac{307}{5 \cdot 2 ^ {2} \cdot 3 ^ {2}} = 1\frac{127}{180} = 1.7055555555555555$$