Solve 1.591.0*10^3*15*115^2/3*19^2

$$1.59 \frac { 1.0 \times 10 ^ { 3 } \times 15 \times 115 ^ { 2 } } { 3 \times 19 ^ { 2 } }$$

Evaluate

$$\frac{105138750}{361}\approx 291243.074792244$$

Solution Steps

Cancel out 3 in both numerator and denominator.

$$1.59\times \frac{5\times 10^{3}\times 115^{2}}{19^{2}}$$

Calculate 10 to the power of 3 and get 1000.

$$1.59\times \frac{5\times 1000\times 115^{2}}{19^{2}}$$

Multiply 5 and 1000 to get 5000.

$$1.59\times \frac{5000\times 115^{2}}{19^{2}}$$

Calculate 115 to the power of 2 and get 13225.

$$1.59\times \frac{5000\times 13225}{19^{2}}$$

Multiply 5000 and 13225 to get 66125000.

$$1.59\times \frac{66125000}{19^{2}}$$

Calculate 19 to the power of 2 and get 361.

$$1.59\times \frac{66125000}{361}$$

Convert decimal number 1.59 to fraction \frac{159}{100}.

$$\frac{159}{100}\times \frac{66125000}{361}$$

Multiply \frac{159}{100} times \frac{66125000}{361} by multiplying numerator times numerator and denominator times denominator.

$$\frac{159\times 66125000}{100\times 361}$$

Do the multiplications in the fraction \frac{159\times 66125000}{100\times 361}.

$$\frac{10513875000}{36100}$$

Reduce the fraction \frac{10513875000}{36100} to lowest terms by extracting and canceling out 100.

$$\frac{105138750}{361}$$

Factor

$$\frac{2 \cdot 3 \cdot 53 \cdot 5 ^ {4} \cdot 23 ^ {2}}{19 ^ {2}} = 291243\frac{27}{361} = 291243.0747922438$$