Solve 1.12x+0.70y=392

$$1.12 x + 0.70 y = 392$$

Solve for x

$$x=-\frac{5y}{8}+350$$

Steps for Solving Linear Equation

Subtract 0.7y from both sides.

$$1.12x=392-0.7y$$

The equation is in standard form.

$$1.12x=-\frac{7y}{10}+392$$

Divide both sides of the equation by 1.12, which is the same as multiplying both sides by the reciprocal of the fraction.

$$\frac{1.12x}{1.12}=\frac{-\frac{7y}{10}+392}{1.12}$$

Dividing by 1.12 undoes the multiplication by 1.12.

$$x=\frac{-\frac{7y}{10}+392}{1.12}$$

Divide 392-\frac{7y}{10} by 1.12 by multiplying 392-\frac{7y}{10} by the reciprocal of 1.12.

$$x=-\frac{5y}{8}+350$$

Solve for y

$$y=-\frac{8x}{5}+560$$

Steps for Solving Linear Equation

Subtract 1.12x from both sides.

$$0.7y=392-1.12x$$

The equation is in standard form.

$$0.7y=-\frac{28x}{25}+392$$

Divide both sides of the equation by 0.7, which is the same as multiplying both sides by the reciprocal of the fraction.

$$\frac{0.7y}{0.7}=\frac{-\frac{28x}{25}+392}{0.7}$$

Dividing by 0.7 undoes the multiplication by 0.7.

$$y=\frac{-\frac{28x}{25}+392}{0.7}$$

Divide 392-\frac{28x}{25} by 0.7 by multiplying 392-\frac{28x}{25} by the reciprocal of 0.7.

$$y=-\frac{8x}{5}+560$$