Solve 1.06=7.04410^-3*t+1/1.824+t3/0.128*10^7

$$1.06 = \frac{ 7.044 { 10 }^{ -3 } \times t+1 }{ 1.824 } + \frac{ t3 }{ 0.128 \times { 10 }^{ 7 } }$$

Solve for t

$$t=-\frac{19t_{3}}{93920}+\frac{233360}{1761}$$

Steps for Solving Linear Equation

Calculate 10 to the power of -3 and get \frac{1}{1000}.

$$1.06=\frac{7.044\times \frac{1}{1000}t+1}{1.824}+\frac{t_{3}}{0.128\times 10^{7}}$$

Multiply 7.044 and \frac{1}{1000} to get \frac{1761}{250000}.

$$1.06=\frac{\frac{1761}{250000}t+1}{1.824}+\frac{t_{3}}{0.128\times 10^{7}}$$

Calculate 10 to the power of 7 and get 10000000.

$$1.06=\frac{\frac{1761}{250000}t+1}{1.824}+\frac{t_{3}}{0.128\times 10000000}$$

Multiply 0.128 and 10000000 to get 1280000.

$$1.06=\frac{\frac{1761}{250000}t+1}{1.824}+\frac{t_{3}}{1280000}$$

Divide each term of \frac{1761}{250000}t+1 by 1.824 to get \frac{\frac{1761}{250000}t}{1.824}+\frac{1}{1.824}.

$$1.06=\frac{\frac{1761}{250000}t}{1.824}+\frac{1}{1.824}+\frac{t_{3}}{1280000}$$

Divide \frac{1761}{250000}t by 1.824 to get \frac{587}{152000}t.

$$1.06=\frac{587}{152000}t+\frac{1}{1.824}+\frac{t_{3}}{1280000}$$

Expand \frac{1}{1.824} by multiplying both numerator and the denominator by 1000.

$$1.06=\frac{587}{152000}t+\frac{1000}{1824}+\frac{t_{3}}{1280000}$$

Reduce the fraction \frac{1000}{1824} to lowest terms by extracting and canceling out 8.

$$1.06=\frac{587}{152000}t+\frac{125}{228}+\frac{t_{3}}{1280000}$$

To add or subtract expressions, expand them to make their denominators the same. Least common multiple of 228 and 1280000 is 72960000. Multiply \frac{125}{228} times \frac{320000}{320000}. Multiply \frac{t_{3}}{1280000} times \frac{57}{57}.

$$1.06=\frac{587}{152000}t+\frac{125\times 320000}{72960000}+\frac{57t_{3}}{72960000}$$

Since \frac{125\times 320000}{72960000} and \frac{57t_{3}}{72960000} have the same denominator, add them by adding their numerators.

$$1.06=\frac{587}{152000}t+\frac{125\times 320000+57t_{3}}{72960000}$$

Do the multiplications in 125\times 320000+57t_{3}.

$$1.06=\frac{587}{152000}t+\frac{40000000+57t_{3}}{72960000}$$

Swap sides so that all variable terms are on the left hand side.

$$\frac{587}{152000}t+\frac{40000000+57t_{3}}{72960000}=1.06$$

Divide each term of 40000000+57t_{3} by 72960000 to get \frac{125}{228}+\frac{1}{1280000}t_{3}.

$$\frac{587}{152000}t+\frac{125}{228}+\frac{1}{1280000}t_{3}=1.06$$

Subtract \frac{125}{228} from both sides.

$$\frac{587}{152000}t+\frac{1}{1280000}t_{3}=1.06-\frac{125}{228}$$

Subtract \frac{125}{228} from 1.06 to get \frac{2917}{5700}.

$$\frac{587}{152000}t+\frac{1}{1280000}t_{3}=\frac{2917}{5700}$$

Subtract \frac{1}{1280000}t_{3} from both sides.

$$\frac{587}{152000}t=\frac{2917}{5700}-\frac{1}{1280000}t_{3}$$

The equation is in standard form.

$$\frac{587}{152000}t=-\frac{t_{3}}{1280000}+\frac{2917}{5700}$$

Divide both sides of the equation by \frac{587}{152000}, which is the same as multiplying both sides by the reciprocal of the fraction.

$$\frac{\frac{587}{152000}t}{\frac{587}{152000}}=\frac{-\frac{t_{3}}{1280000}+\frac{2917}{5700}}{\frac{587}{152000}}$$

Dividing by \frac{587}{152000} undoes the multiplication by \frac{587}{152000}.

$$t=\frac{-\frac{t_{3}}{1280000}+\frac{2917}{5700}}{\frac{587}{152000}}$$

Divide \frac{2917}{5700}-\frac{t_{3}}{1280000} by \frac{587}{152000} by multiplying \frac{2917}{5700}-\frac{t_{3}}{1280000} by the reciprocal of \frac{587}{152000}.

$$t=-\frac{19t_{3}}{93920}+\frac{233360}{1761}$$

Solve for t_3

$$t_{3}=-\frac{93920t}{19}+\frac{37337600}{57}$$

Steps for Solving Linear Equation

Calculate 10 to the power of -3 and get \frac{1}{1000}.

$$1.06=\frac{7.044\times \frac{1}{1000}t+1}{1.824}+\frac{t_{3}}{0.128\times 10^{7}}$$

Multiply 7.044 and \frac{1}{1000} to get \frac{1761}{250000}.

$$1.06=\frac{\frac{1761}{250000}t+1}{1.824}+\frac{t_{3}}{0.128\times 10^{7}}$$

Calculate 10 to the power of 7 and get 10000000.

$$1.06=\frac{\frac{1761}{250000}t+1}{1.824}+\frac{t_{3}}{0.128\times 10000000}$$

Multiply 0.128 and 10000000 to get 1280000.

$$1.06=\frac{\frac{1761}{250000}t+1}{1.824}+\frac{t_{3}}{1280000}$$

Divide each term of \frac{1761}{250000}t+1 by 1.824 to get \frac{\frac{1761}{250000}t}{1.824}+\frac{1}{1.824}.

$$1.06=\frac{\frac{1761}{250000}t}{1.824}+\frac{1}{1.824}+\frac{t_{3}}{1280000}$$

Divide \frac{1761}{250000}t by 1.824 to get \frac{587}{152000}t.

$$1.06=\frac{587}{152000}t+\frac{1}{1.824}+\frac{t_{3}}{1280000}$$

Expand \frac{1}{1.824} by multiplying both numerator and the denominator by 1000.

$$1.06=\frac{587}{152000}t+\frac{1000}{1824}+\frac{t_{3}}{1280000}$$

Reduce the fraction \frac{1000}{1824} to lowest terms by extracting and canceling out 8.

$$1.06=\frac{587}{152000}t+\frac{125}{228}+\frac{t_{3}}{1280000}$$

To add or subtract expressions, expand them to make their denominators the same. Least common multiple of 228 and 1280000 is 72960000. Multiply \frac{125}{228} times \frac{320000}{320000}. Multiply \frac{t_{3}}{1280000} times \frac{57}{57}.

$$1.06=\frac{587}{152000}t+\frac{125\times 320000}{72960000}+\frac{57t_{3}}{72960000}$$

Since \frac{125\times 320000}{72960000} and \frac{57t_{3}}{72960000} have the same denominator, add them by adding their numerators.

$$1.06=\frac{587}{152000}t+\frac{125\times 320000+57t_{3}}{72960000}$$

Do the multiplications in 125\times 320000+57t_{3}.

$$1.06=\frac{587}{152000}t+\frac{40000000+57t_{3}}{72960000}$$

Swap sides so that all variable terms are on the left hand side.

$$\frac{587}{152000}t+\frac{40000000+57t_{3}}{72960000}=1.06$$

Divide each term of 40000000+57t_{3} by 72960000 to get \frac{125}{228}+\frac{1}{1280000}t_{3}.

$$\frac{587}{152000}t+\frac{125}{228}+\frac{1}{1280000}t_{3}=1.06$$

Subtract \frac{587}{152000}t from both sides.

$$\frac{125}{228}+\frac{1}{1280000}t_{3}=1.06-\frac{587}{152000}t$$

Subtract \frac{125}{228} from both sides.

$$\frac{1}{1280000}t_{3}=1.06-\frac{587}{152000}t-\frac{125}{228}$$

Subtract \frac{125}{228} from 1.06 to get \frac{2917}{5700}.

$$\frac{1}{1280000}t_{3}=\frac{2917}{5700}-\frac{587}{152000}t$$

The equation is in standard form.

$$\frac{1}{1280000}t_{3}=-\frac{587t}{152000}+\frac{2917}{5700}$$

Multiply both sides by 1280000.

$$\frac{\frac{1}{1280000}t_{3}}{\frac{1}{1280000}}=\frac{-\frac{587t}{152000}+\frac{2917}{5700}}{\frac{1}{1280000}}$$

Dividing by \frac{1}{1280000} undoes the multiplication by \frac{1}{1280000}.

$$t_{3}=\frac{-\frac{587t}{152000}+\frac{2917}{5700}}{\frac{1}{1280000}}$$

Divide \frac{2917}{5700}-\frac{587t}{152000} by \frac{1}{1280000} by multiplying \frac{2917}{5700}-\frac{587t}{152000} by the reciprocal of \frac{1}{1280000}.

$$t_{3}=-\frac{93920t}{19}+\frac{37337600}{57}$$