Solve 1.02^12+(2*1.02^9)+(2*1.0)

$$1.02 ^ { 12 } + ( 2 \cdot 1.02 ^ { 9 } ) + ( 2 \cdot 1.0 )$$

Evaluate

$$5.658426931807167142301696$$

Solution Steps

Calculate 1.02 to the power of 12 and get 1.268241794562545318301696.

$$1.268241794562545318301696+2\times 1.02^{9}+2\times 1$$

Calculate 1.02 to the power of 9 and get 1.195092568622310912.

$$1.268241794562545318301696+2\times 1.195092568622310912+2\times 1$$

Multiply 2 and 1.195092568622310912 to get 2.390185137244621824.

$$1.268241794562545318301696+2.390185137244621824+2\times 1$$

Add 1.268241794562545318301696 and 2.390185137244621824 to get 3.658426931807167142301696.

$$3.658426931807167142301696+2\times 1$$

Multiply 2 and 1 to get 2.

$$3.658426931807167142301696+2$$

Add 3.658426931807167142301696 and 2 to get 5.658426931807167142301696.

$$5.658426931807167142301696$$

Factor

$$\frac{71089 \cdot 19432709528172209}{2 ^ {12} \cdot 5 ^ {24}} = 5\frac{1.6074876264823403 \times 10^{20}}{2.44140625 \times 10^{20}} = 5.658426931807167$$