Solve 1-(365*02)=1div(1+(365*x))

$$1-(365 \times 02)=1 \div (1+(365 \times x))$$

Solve for x

$$x=0$$

Steps for Solving Linear Equation

Variable x cannot be equal to -\frac{1}{365} since division by zero is not defined. Multiply both sides of the equation by 365x+1.

$$365x+1-365\times 0\times 2\left(365x+1\right)=1$$

Multiply 365 and 0 to get 0.

$$365x+1-0\times 2\left(365x+1\right)=1$$

Multiply 0 and 2 to get 0.

$$365x+1-0\left(365x+1\right)=1$$

Anything times zero gives zero.

$$365x+1-0=1$$

Add 0 to both sides.

$$365x+1=1+0$$

Add 1 and 0 to get 1.

$$365x+1=1$$

Subtract 1 from both sides.

$$365x=1-1$$

Subtract 1 from 1 to get 0.

$$365x=0$$

Product of two numbers is equal to 0 if at least one of them is 0. Since 365 is not equal to 0, x must be equal to 0.

$$x=0$$