Solve 1,02*10^10*1,602*10^-9*(1450+500)

$$1,02 \times 10 ^ { 10 } \times 1,602 \times 10 ^ { - 9 } \times ( 1450 + 500 )$$

Evaluate

$$31863,78$$

Solution Steps

To multiply powers of the same base, add their exponents. Add 10 and -9 to get 1.

$$1,02\times 10^{1}\times 1,602\left(1450+500\right)$$

Calculate 10 to the power of 1 and get 10.

$$1,02\times 10\times 1,602\left(1450+500\right)$$

Multiply 1,02 and 10 to get 10,2.

$$10,2\times 1,602\left(1450+500\right)$$

Multiply 10,2 and 1,602 to get 16,3404.

$$16,3404\left(1450+500\right)$$

Add 1450 and 500 to get 1950.

$$16,3404\times 1950$$

Multiply 16,3404 and 1950 to get 31863,78.

$$31863,78$$

Factor

$$\frac{13 \cdot 17 \cdot 89 \cdot 3 ^ {4}}{2 \cdot 5 ^ {2}} = 31863\frac{39}{50} = 31863.78$$