Solve 1+x(4/3)=4/3-x

$$1+x( \frac{ 4 }{ 3 } )= \frac{ 4 }{ 3 } -x$$

Solve for x

$$x=\frac{1}{7}\approx 0.142857143$$

Steps for Solving Linear Equation

Add x to both sides.

$$1+x\times \frac{4}{3}+x=\frac{4}{3}$$

Combine x\times \frac{4}{3} and x to get \frac{7}{3}x.

$$1+\frac{7}{3}x=\frac{4}{3}$$

Subtract 1 from both sides.

$$\frac{7}{3}x=\frac{4}{3}-1$$

Convert 1 to fraction \frac{3}{3}.

$$\frac{7}{3}x=\frac{4}{3}-\frac{3}{3}$$

Since \frac{4}{3} and \frac{3}{3} have the same denominator, subtract them by subtracting their numerators.

$$\frac{7}{3}x=\frac{4-3}{3}$$

Subtract 3 from 4 to get 1.

$$\frac{7}{3}x=\frac{1}{3}$$

Multiply both sides by \frac{3}{7}, the reciprocal of \frac{7}{3}.

$$x=\frac{1}{3}\times \frac{3}{7}$$

Multiply \frac{1}{3} times \frac{3}{7} by multiplying numerator times numerator and denominator times denominator.

$$x=\frac{1\times 3}{3\times 7}$$

Cancel out 3 in both numerator and denominator.

$$x=\frac{1}{7}$$