Solve 1+1=xx.360=

$$1+1=xx.360=$$

Solve for x

$$x = \frac{5 \sqrt{2}}{3} \approx 2.357022604$$

$$x = -\frac{5 \sqrt{2}}{3} \approx -2.357022604$$

Steps by Finding Square Root

Multiply x and x to get x^{2}.

$$1+1=x^{2}\times 0.36$$

Add 1 and 1 to get 2.

$$2=x^{2}\times 0.36$$

Swap sides so that all variable terms are on the left hand side.

$$x^{2}\times 0.36=2$$

Divide both sides by 0.36.

$$x^{2}=\frac{2}{0.36}$$

Expand \frac{2}{0.36} by multiplying both numerator and the denominator by 100.

$$x^{2}=\frac{200}{36}$$

Reduce the fraction \frac{200}{36} to lowest terms by extracting and canceling out 4.

$$x^{2}=\frac{50}{9}$$

Take the square root of both sides of the equation.

$$x=\frac{5\sqrt{2}}{3} x=-\frac{5\sqrt{2}}{3}$$

Steps Using the Quadratic Formula

Multiply x and x to get x^{2}.

$$1+1=x^{2}\times 0.36$$

Add 1 and 1 to get 2.

$$2=x^{2}\times 0.36$$

Swap sides so that all variable terms are on the left hand side.

$$x^{2}\times 0.36=2$$

Subtract 2 from both sides.

$$x^{2}\times 0.36-2=0$$

Quadratic equations like this one, with an x^{2} term but no x term, can still be solved using the quadratic formula, \frac{-b±\sqrt{b^{2}-4ac}}{2a}, once they are put in standard form: ax^{2}+bx+c=0.

$$0.36x^{2}-2=0$$

This equation is in standard form: ax^{2}+bx+c=0. Substitute 0.36 for a, 0 for b, and -2 for c in the quadratic formula, \frac{-b±\sqrt{b^{2}-4ac}}{2a}.

$$x=\frac{0±\sqrt{0^{2}-4\times 0.36\left(-2\right)}}{2\times 0.36}$$

Square 0.

$$x=\frac{0±\sqrt{-4\times 0.36\left(-2\right)}}{2\times 0.36}$$

Multiply -4 times 0.36.

$$x=\frac{0±\sqrt{-1.44\left(-2\right)}}{2\times 0.36}$$

Multiply -1.44 times -2.

$$x=\frac{0±\sqrt{2.88}}{2\times 0.36}$$

Take the square root of 2.88.

$$x=\frac{0±\frac{6\sqrt{2}}{5}}{2\times 0.36}$$

Multiply 2 times 0.36.

$$x=\frac{0±\frac{6\sqrt{2}}{5}}{0.72}$$

Now solve the equation x=\frac{0±\frac{6\sqrt{2}}{5}}{0.72} when ± is plus.

$$x=\frac{5\sqrt{2}}{3}$$

Now solve the equation x=\frac{0±\frac{6\sqrt{2}}{5}}{0.72} when ± is minus.

$$x=-\frac{5\sqrt{2}}{3}$$

The equation is now solved.

$$x=\frac{5\sqrt{2}}{3} x=-\frac{5\sqrt{2}}{3}$$