Solve for x
x=5
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1x+2-2x-\left(-8\right)=x
To find the opposite of 2x-8, find the opposite of each term.
1x+2-2x+8=x
The opposite of -8 is 8.
-x+2+8=x
Combine 1x and -2x to get -x.
-x+10=x
Add 2 and 8 to get 10.
-x+10-x=0
Subtract x from both sides.
-2x+10=0
Combine -x and -x to get -2x.
-2x=-10
Subtract 10 from both sides. Anything subtracted from zero gives its negation.
x=\frac{-10}{-2}
Divide both sides by -2.
x=5
Divide -10 by -2 to get 5.
Examples
Quadratic equation
{ x } ^ { 2 } - 4 x - 5 = 0
Trigonometry
4 \sin \theta \cos \theta = 2 \sin \theta
Linear equation
y = 3x + 4
Arithmetic
699 * 533
Matrix
\left[ \begin{array} { l l } { 2 } & { 3 } \\ { 5 } & { 4 } \end{array} \right] \left[ \begin{array} { l l l } { 2 } & { 0 } & { 3 } \\ { -1 } & { 1 } & { 5 } \end{array} \right]
Simultaneous equation
\left. \begin{cases} { 8x+2y = 46 } \\ { 7x+3y = 47 } \end{cases} \right.
Differentiation
\frac { d } { d x } \frac { ( 3 x ^ { 2 } - 2 ) } { ( x - 5 ) }
Integration
\int _ { 0 } ^ { 1 } x e ^ { - x ^ { 2 } } d x
Limits
\lim _{x \rightarrow-3} \frac{x^{2}-9}{x^{2}+2 x-3}