Solve 1ve:3x/4+x/6=22

$$1 v e : \frac { 3 x } { 4 } + \frac { x } { 6 } = 22$$

Solve for v

$$v=-\frac{x\left(x-132\right)}{8e}$$

$$x\neq 0$$

Steps for Solving Linear Equation

Multiply both sides of the equation by 6.

$$8x^{-1}\times 1ve+x=132$$

Multiply 8 and 1 to get 8.

$$8x^{-1}ve+x=132$$

Subtract x from both sides.

$$8x^{-1}ve=132-x$$

Reorder the terms.

$$8e\times \frac{1}{x}v=-x+132$$

Multiply both sides of the equation by x.

$$8e\times 1v=-xx+x\times 132$$

Multiply x and x to get x^{2}.

$$8e\times 1v=-x^{2}+x\times 132$$

Multiply 8 and 1 to get 8.

$$8ev=-x^{2}+x\times 132$$

The equation is in standard form.

$$8ev=132x-x^{2}$$

Divide both sides by 8e.

$$\frac{8ev}{8e}=\frac{x\left(132-x\right)}{8e}$$

Dividing by 8e undoes the multiplication by 8e.

$$v=\frac{x\left(132-x\right)}{8e}$$

Solve for x (complex solution)

$$\left\{\begin{matrix}\\x=2\sqrt{1089-2ev}+66\text{, }&\text{unconditionally}\\x=-2\sqrt{1089-2ev}+66\text{, }&v\neq 0\end{matrix}\right.$$

Solve for x

$$\left\{\begin{matrix}x=-2\sqrt{1089-2ev}+66\text{, }&v\neq 0\text{ and }v\leq \frac{1089}{2e}\\x=2\sqrt{1089-2ev}+66\text{, }&v\leq \frac{1089}{2e}\end{matrix}\right.$$