Solve 1-61/21:13/15-4,2

$$1 - 6 \frac { 1 } { 2 } 1 : \frac { 13 } { 15 } - 4,2$$

Evaluate

$$-10,7$$

Solution Steps

Multiply 6 and 2 to get 12.

$$1-\frac{\frac{12+1}{2}\times 1}{\frac{13}{15}}-4,2$$

Add 12 and 1 to get 13.

$$1-\frac{\frac{13}{2}\times 1}{\frac{13}{15}}-4,2$$

Multiply \frac{13}{2} and 1 to get \frac{13}{2}.

$$1-\frac{\frac{13}{2}}{\frac{13}{15}}-4,2$$

Divide \frac{13}{2} by \frac{13}{15} by multiplying \frac{13}{2} by the reciprocal of \frac{13}{15}.

$$1-\frac{13}{2}\times \frac{15}{13}-4,2$$

Multiply \frac{13}{2} times \frac{15}{13} by multiplying numerator times numerator and denominator times denominator.

$$1-\frac{13\times 15}{2\times 13}-4,2$$

Cancel out 13 in both numerator and denominator.

$$1-\frac{15}{2}-4,2$$

Convert 1 to fraction \frac{2}{2}.

$$\frac{2}{2}-\frac{15}{2}-4,2$$

Since \frac{2}{2} and \frac{15}{2} have the same denominator, subtract them by subtracting their numerators.

$$\frac{2-15}{2}-4,2$$

Subtract 15 from 2 to get -13.

$$-\frac{13}{2}-4,2$$

Convert decimal number 4,2 to fraction \frac{42}{10}. Reduce the fraction \frac{42}{10} to lowest terms by extracting and canceling out 2.

$$-\frac{13}{2}-\frac{21}{5}$$

Least common multiple of 2 and 5 is 10. Convert -\frac{13}{2} and \frac{21}{5} to fractions with denominator 10.

$$-\frac{65}{10}-\frac{42}{10}$$

Since -\frac{65}{10} and \frac{42}{10} have the same denominator, subtract them by subtracting their numerators.

$$\frac{-65-42}{10}$$

Subtract 42 from -65 to get -107.

$$-\frac{107}{10}$$

Factor

$$-10,7$$