Solve 1-40x^2+x^4+-380/x^2

$$1 - 40 x ^ { 2 } + x ^ { 4 } + \frac { - 380 } { x ^ { 2 } }$$

Evaluate

$$x^{4}-40x^{2}+1-\frac{380}{x^{2}}$$

Short Solution Steps

To add or subtract expressions, expand them to make their denominators the same. Multiply 1-40x^{2}+x^{4} times \frac{x^{2}}{x^{2}}.

$$\frac{\left(1-40x^{2}+x^{4}\right)x^{2}}{x^{2}}+\frac{-380}{x^{2}}$$

Since \frac{\left(1-40x^{2}+x^{4}\right)x^{2}}{x^{2}} and \frac{-380}{x^{2}} have the same denominator, add them by adding their numerators.

$$\frac{\left(1-40x^{2}+x^{4}\right)x^{2}-380}{x^{2}}$$

Do the multiplications in \left(1-40x^{2}+x^{4}\right)x^{2}-380.

$$\frac{x^{2}-40x^{4}+x^{6}-380}{x^{2}}$$

Factor

$$\frac{x^{6}-40x^{4}+x^{2}-380}{x^{2}}$$