Solve 1-3(x+1)geq6-x

$$1 - 3 ( x + 1 ) \geq 6 - x$$

Solve for x

$$x\leq -4$$

Solution Steps

Use the distributive property to multiply -3 by x+1.

$$1-3x-3\geq 6-x$$

Subtract 3 from 1 to get -2.

$$-2-3x\geq 6-x$$

Add x to both sides.

$$-2-3x+x\geq 6$$

Combine -3x and x to get -2x.

$$-2-2x\geq 6$$

Add 2 to both sides.

$$-2x\geq 6+2$$

Add 6 and 2 to get 8.

$$-2x\geq 8$$

Divide both sides by -2. Since -2 is negative, the inequality direction is changed.

$$x\leq \frac{8}{-2}$$

Divide 8 by -2 to get -4.

$$x\leq -4$$