Solve 1-2^2-2*-2*-5+5*31

$$1 - 2 ^ { 2 } - 2 \cdot - 2 \cdot - 5 + 5 \cdot 31$$

Evaluate

$$132$$

Solution Steps

Calculate 2 to the power of 2 and get 4.

$$1-4-2\left(-2\right)\left(-5\right)+5\times 31$$

Subtract 4 from 1 to get -3.

$$-3-2\left(-2\right)\left(-5\right)+5\times 31$$

Multiply 2 and -2 to get -4.

$$-3-\left(-4\left(-5\right)\right)+5\times 31$$

Multiply -4 and -5 to get 20.

$$-3-20+5\times 31$$

Subtract 20 from -3 to get -23.

$$-23+5\times 31$$

Multiply 5 and 31 to get 155.

$$-23+155$$

Add -23 and 155 to get 132.

$$132$$

Factor

$$2^{2}\times 3\times 11$$