Solve for x
x>-\frac{1}{4}
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1-3x-\left(-2\right)<4+x
To find the opposite of 3x-2, find the opposite of each term.
1-3x+2<4+x
The opposite of -2 is 2.
3-3x<4+x
Add 1 and 2 to get 3.
3-3x-x<4
Subtract x from both sides.
3-4x<4
Combine -3x and -x to get -4x.
-4x<4-3
Subtract 3 from both sides.
-4x<1
Subtract 3 from 4 to get 1.
x>-\frac{1}{4}
Divide both sides by -4. Since -4 is negative, the inequality direction is changed.
Examples
Quadratic equation
{ x } ^ { 2 } - 4 x - 5 = 0
Trigonometry
4 \sin \theta \cos \theta = 2 \sin \theta
Linear equation
y = 3x + 4
Arithmetic
699 * 533
Matrix
\left[ \begin{array} { l l } { 2 } & { 3 } \\ { 5 } & { 4 } \end{array} \right] \left[ \begin{array} { l l l } { 2 } & { 0 } & { 3 } \\ { -1 } & { 1 } & { 5 } \end{array} \right]
Simultaneous equation
\left. \begin{cases} { 8x+2y = 46 } \\ { 7x+3y = 47 } \end{cases} \right.
Differentiation
\frac { d } { d x } \frac { ( 3 x ^ { 2 } - 2 ) } { ( x - 5 ) }
Integration
\int _ { 0 } ^ { 1 } x e ^ { - x ^ { 2 } } d x
Limits
\lim _{x \rightarrow-3} \frac{x^{2}-9}{x^{2}+2 x-3}