Solve 1-(1/3+2^3*1/4)div3/2=

$$1 - ( \frac { 1 } { 3 } + 2 ^ { 3 } \times \frac { 1 } { 4 } ) \div \frac { 3 } { 2 } =$$

Evaluate

$$-\frac{5}{9}\approx -0.555555556$$

Solution Steps

Calculate 2 to the power of 3 and get 8.

$$1-\frac{\frac{1}{3}+8\times \frac{1}{4}}{\frac{3}{2}}$$

Multiply 8 and \frac{1}{4} to get \frac{8}{4}.

$$1-\frac{\frac{1}{3}+\frac{8}{4}}{\frac{3}{2}}$$

Divide 8 by 4 to get 2.

$$1-\frac{\frac{1}{3}+2}{\frac{3}{2}}$$

Convert 2 to fraction \frac{6}{3}.

$$1-\frac{\frac{1}{3}+\frac{6}{3}}{\frac{3}{2}}$$

Since \frac{1}{3} and \frac{6}{3} have the same denominator, add them by adding their numerators.

$$1-\frac{\frac{1+6}{3}}{\frac{3}{2}}$$

Add 1 and 6 to get 7.

$$1-\frac{\frac{7}{3}}{\frac{3}{2}}$$

Divide \frac{7}{3} by \frac{3}{2} by multiplying \frac{7}{3} by the reciprocal of \frac{3}{2}.

$$1-\frac{7}{3}\times \frac{2}{3}$$

Multiply \frac{7}{3} times \frac{2}{3} by multiplying numerator times numerator and denominator times denominator.

$$1-\frac{7\times 2}{3\times 3}$$

Do the multiplications in the fraction \frac{7\times 2}{3\times 3}.

$$1-\frac{14}{9}$$

Convert 1 to fraction \frac{9}{9}.

$$\frac{9}{9}-\frac{14}{9}$$

Since \frac{9}{9} and \frac{14}{9} have the same denominator, subtract them by subtracting their numerators.

$$\frac{9-14}{9}$$

Subtract 14 from 9 to get -5.

$$-\frac{5}{9}$$

Factor

$$-\frac{5}{9} = -0.5555555555555556$$