Solve 1-2/9-3/7=7/9

$$1 - \frac { 2 } { 9 } - \frac { 3 } { 7 } = \frac { 7 } { 9 }$$

Verify

Solution Steps

Convert 1 to fraction \frac{9}{9}.

$$\frac{9}{9}-\frac{2}{9}-\frac{3}{7}=\frac{7}{9}$$

Since \frac{9}{9} and \frac{2}{9} have the same denominator, subtract them by subtracting their numerators.

$$\frac{9-2}{9}-\frac{3}{7}=\frac{7}{9}$$

Subtract 2 from 9 to get 7.

$$\frac{7}{9}-\frac{3}{7}=\frac{7}{9}$$

Least common multiple of 9 and 7 is 63. Convert \frac{7}{9} and \frac{3}{7} to fractions with denominator 63.

$$\frac{49}{63}-\frac{27}{63}=\frac{7}{9}$$

Since \frac{49}{63} and \frac{27}{63} have the same denominator, subtract them by subtracting their numerators.

$$\frac{49-27}{63}=\frac{7}{9}$$

Subtract 27 from 49 to get 22.

$$\frac{22}{63}=\frac{7}{9}$$

Least common multiple of 63 and 9 is 63. Convert \frac{22}{63} and \frac{7}{9} to fractions with denominator 63.

$$\frac{22}{63}=\frac{49}{63}$$

Compare \frac{22}{63} and \frac{49}{63}.

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