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\frac{8-p^{3}}{8}
Factor out \frac{1}{8}.
\left(p-2\right)\left(-p^{2}-2p-4\right)
Consider 8-p^{3}. By Rational Root Theorem, all rational roots of a polynomial are in the form \frac{p}{q}, where p divides the constant term 8 and q divides the leading coefficient -1. One such root is 2. Factor the polynomial by dividing it by p-2.
\frac{\left(p-2\right)\left(-p^{2}-2p-4\right)}{8}
Rewrite the complete factored expression. Polynomial -p^{2}-2p-4 is not factored since it does not have any rational roots.