Solve 1-1/20-3/10-1/6-1/60

$$1 - \frac { 1 } { 20 } - \frac { 3 } { 10 } - \frac { 1 } { 6 } - \frac { 1 } { 60 }$$

Evaluate

$$\frac{7}{15}\approx 0.466666667$$

Solution Steps

Convert 1 to fraction \frac{20}{20}.

$$\frac{20}{20}-\frac{1}{20}-\frac{3}{10}-\frac{1}{6}-\frac{1}{60}$$

Since \frac{20}{20} and \frac{1}{20} have the same denominator, subtract them by subtracting their numerators.

$$\frac{20-1}{20}-\frac{3}{10}-\frac{1}{6}-\frac{1}{60}$$

Subtract 1 from 20 to get 19.

$$\frac{19}{20}-\frac{3}{10}-\frac{1}{6}-\frac{1}{60}$$

Least common multiple of 20 and 10 is 20. Convert \frac{19}{20} and \frac{3}{10} to fractions with denominator 20.

$$\frac{19}{20}-\frac{6}{20}-\frac{1}{6}-\frac{1}{60}$$

Since \frac{19}{20} and \frac{6}{20} have the same denominator, subtract them by subtracting their numerators.

$$\frac{19-6}{20}-\frac{1}{6}-\frac{1}{60}$$

Subtract 6 from 19 to get 13.

$$\frac{13}{20}-\frac{1}{6}-\frac{1}{60}$$

Least common multiple of 20 and 6 is 60. Convert \frac{13}{20} and \frac{1}{6} to fractions with denominator 60.

$$\frac{39}{60}-\frac{10}{60}-\frac{1}{60}$$

Since \frac{39}{60} and \frac{10}{60} have the same denominator, subtract them by subtracting their numerators.

$$\frac{39-10}{60}-\frac{1}{60}$$

Subtract 10 from 39 to get 29.

$$\frac{29}{60}-\frac{1}{60}$$

Since \frac{29}{60} and \frac{1}{60} have the same denominator, subtract them by subtracting their numerators.

$$\frac{29-1}{60}$$

Subtract 1 from 29 to get 28.

$$\frac{28}{60}$$

Reduce the fraction \frac{28}{60} to lowest terms by extracting and canceling out 4.

$$\frac{7}{15}$$

Factor

$$\frac{7}{3 \cdot 5} = 0.4666666666666667$$