Solve 1(5*2^2):(3+2^3+3^2)^2

$$1 ( 5 \times 2 ^ { 2 } ) : ( 3 + 2 ^ { 3 } + 3 ^ { 2 } ) ^ { 2 }$$

Evaluate

$$\frac{1}{20}=0.05$$

Solution Steps

Multiply 1 and 5 to get 5.

$$\frac{5\times 2^{2}}{\left(3+2^{3}+3^{2}\right)^{2}}$$

Calculate 2 to the power of 2 and get 4.

$$\frac{5\times 4}{\left(3+2^{3}+3^{2}\right)^{2}}$$

Multiply 5 and 4 to get 20.

$$\frac{20}{\left(3+2^{3}+3^{2}\right)^{2}}$$

Calculate 2 to the power of 3 and get 8.

$$\frac{20}{\left(3+8+3^{2}\right)^{2}}$$

Add 3 and 8 to get 11.

$$\frac{20}{\left(11+3^{2}\right)^{2}}$$

Calculate 3 to the power of 2 and get 9.

$$\frac{20}{\left(11+9\right)^{2}}$$

Add 11 and 9 to get 20.

$$\frac{20}{20^{2}}$$

Calculate 20 to the power of 2 and get 400.

$$\frac{20}{400}$$

Reduce the fraction \frac{20}{400} to lowest terms by extracting and canceling out 20.

$$\frac{1}{20}$$

Factor

$$\frac{1}{2 ^ {2} \cdot 5} = 0.05$$