Solve 11/2-31/2-52/3-32/3-5

$$1 \frac{ 1 }{ 2 } -3 \frac{ 1 }{ 2 } -5 \frac{ 2 }{ 3 } -3 \frac{ 2 }{ 3 } -5$$

Evaluate

$$-\frac{49}{3}\approx -16.333333333$$

Solution Steps

Multiply 1 and 2 to get 2.

$$\frac{2+1}{2}-\frac{3\times 2+1}{2}-\frac{5\times 3+2}{3}-\frac{3\times 3+2}{3}-5$$

Add 2 and 1 to get 3.

$$\frac{3}{2}-\frac{3\times 2+1}{2}-\frac{5\times 3+2}{3}-\frac{3\times 3+2}{3}-5$$

Multiply 3 and 2 to get 6.

$$\frac{3}{2}-\frac{6+1}{2}-\frac{5\times 3+2}{3}-\frac{3\times 3+2}{3}-5$$

Add 6 and 1 to get 7.

$$\frac{3}{2}-\frac{7}{2}-\frac{5\times 3+2}{3}-\frac{3\times 3+2}{3}-5$$

Since \frac{3}{2} and \frac{7}{2} have the same denominator, subtract them by subtracting their numerators.

$$\frac{3-7}{2}-\frac{5\times 3+2}{3}-\frac{3\times 3+2}{3}-5$$

Subtract 7 from 3 to get -4.

$$\frac{-4}{2}-\frac{5\times 3+2}{3}-\frac{3\times 3+2}{3}-5$$

Divide -4 by 2 to get -2.

$$-2-\frac{5\times 3+2}{3}-\frac{3\times 3+2}{3}-5$$

Multiply 5 and 3 to get 15.

$$-2-\frac{15+2}{3}-\frac{3\times 3+2}{3}-5$$

Add 15 and 2 to get 17.

$$-2-\frac{17}{3}-\frac{3\times 3+2}{3}-5$$

Convert -2 to fraction -\frac{6}{3}.

$$-\frac{6}{3}-\frac{17}{3}-\frac{3\times 3+2}{3}-5$$

Since -\frac{6}{3} and \frac{17}{3} have the same denominator, subtract them by subtracting their numerators.

$$\frac{-6-17}{3}-\frac{3\times 3+2}{3}-5$$

Subtract 17 from -6 to get -23.

$$-\frac{23}{3}-\frac{3\times 3+2}{3}-5$$

Multiply 3 and 3 to get 9.

$$-\frac{23}{3}-\frac{9+2}{3}-5$$

Add 9 and 2 to get 11.

$$-\frac{23}{3}-\frac{11}{3}-5$$

Since -\frac{23}{3} and \frac{11}{3} have the same denominator, subtract them by subtracting their numerators.

$$\frac{-23-11}{3}-5$$

Subtract 11 from -23 to get -34.

$$-\frac{34}{3}-5$$

Convert 5 to fraction \frac{15}{3}.

$$-\frac{34}{3}-\frac{15}{3}$$

Since -\frac{34}{3} and \frac{15}{3} have the same denominator, subtract them by subtracting their numerators.

$$\frac{-34-15}{3}$$

Subtract 15 from -34 to get -49.

$$-\frac{49}{3}$$

Factor

$$-\frac{49}{3} = -16\frac{1}{3} = -16.333333333333332$$