Solve 11/2(23/4+6/4)

$$1 \frac{ 1 }{ 2 } (2 \frac{ 3 }{ 4 } + \frac{ 6 }{ 4 } )$$

Evaluate

$$\frac{51}{8}=6.375$$

Solution Steps

Multiply 1 and 2 to get 2.

$$\frac{2+1}{2}\left(\frac{2\times 4+3}{4}+\frac{6}{4}\right)$$

Add 2 and 1 to get 3.

$$\frac{3}{2}\left(\frac{2\times 4+3}{4}+\frac{6}{4}\right)$$

Multiply 2 and 4 to get 8.

$$\frac{3}{2}\left(\frac{8+3}{4}+\frac{6}{4}\right)$$

Add 8 and 3 to get 11.

$$\frac{3}{2}\left(\frac{11}{4}+\frac{6}{4}\right)$$

Since \frac{11}{4} and \frac{6}{4} have the same denominator, add them by adding their numerators.

$$\frac{3}{2}\times \frac{11+6}{4}$$

Add 11 and 6 to get 17.

$$\frac{3}{2}\times \frac{17}{4}$$

Multiply \frac{3}{2} times \frac{17}{4} by multiplying numerator times numerator and denominator times denominator.

$$\frac{3\times 17}{2\times 4}$$

Do the multiplications in the fraction \frac{3\times 17}{2\times 4}.

$$\frac{51}{8}$$

Factor

$$\frac{3 \cdot 17}{2 ^ {3}} = 6\frac{3}{8} = 6.375$$