Solve 17/9*32/5*21/12

$$1 \frac { 7 } { 9 } \times 3 \frac { 2 } { 5 } \times 2 \frac { 1 } { 12 }$$

Evaluate

$$\frac{340}{27}\approx 12.592592593$$

Solution Steps

Multiply 1 and 9 to get 9.

$$\frac{9+7}{9}\times \frac{3\times 5+2}{5}\times \frac{2\times 12+1}{12}$$

Add 9 and 7 to get 16.

$$\frac{16}{9}\times \frac{3\times 5+2}{5}\times \frac{2\times 12+1}{12}$$

Multiply 3 and 5 to get 15.

$$\frac{16}{9}\times \frac{15+2}{5}\times \frac{2\times 12+1}{12}$$

Add 15 and 2 to get 17.

$$\frac{16}{9}\times \frac{17}{5}\times \frac{2\times 12+1}{12}$$

Multiply \frac{16}{9} times \frac{17}{5} by multiplying numerator times numerator and denominator times denominator.

$$\frac{16\times 17}{9\times 5}\times \frac{2\times 12+1}{12}$$

Do the multiplications in the fraction \frac{16\times 17}{9\times 5}.

$$\frac{272}{45}\times \frac{2\times 12+1}{12}$$

Multiply 2 and 12 to get 24.

$$\frac{272}{45}\times \frac{24+1}{12}$$

Add 24 and 1 to get 25.

$$\frac{272}{45}\times \frac{25}{12}$$

Multiply \frac{272}{45} times \frac{25}{12} by multiplying numerator times numerator and denominator times denominator.

$$\frac{272\times 25}{45\times 12}$$

Do the multiplications in the fraction \frac{272\times 25}{45\times 12}.

$$\frac{6800}{540}$$

Reduce the fraction \frac{6800}{540} to lowest terms by extracting and canceling out 20.

$$\frac{340}{27}$$

Factor

$$\frac{2 ^ {2} \cdot 5 \cdot 17}{3 ^ {3}} = 12\frac{16}{27} = 12.592592592592593$$