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\frac{\left(1\times 4+3\right)\times 20}{4\times 9}
Divide \frac{1\times 4+3}{4} by \frac{9}{20} by multiplying \frac{1\times 4+3}{4} by the reciprocal of \frac{9}{20}.
\frac{5\left(3+4\right)}{9}
Cancel out 4 in both numerator and denominator.
\frac{5\times 7}{9}
Add 3 and 4 to get 7.
\frac{35}{9}
Multiply 5 and 7 to get 35.