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\frac{\left(1\times 3+1\right)\times 5}{3\times 2}
Divide \frac{1\times 3+1}{3} by \frac{2}{5} by multiplying \frac{1\times 3+1}{3} by the reciprocal of \frac{2}{5}.
\frac{\left(3+1\right)\times 5}{3\times 2}
Multiply 1 and 3 to get 3.
\frac{4\times 5}{3\times 2}
Add 3 and 1 to get 4.
\frac{20}{3\times 2}
Multiply 4 and 5 to get 20.
\frac{20}{6}
Multiply 3 and 2 to get 6.
\frac{10}{3}
Reduce the fraction \frac{20}{6} to lowest terms by extracting and canceling out 2.