Solve 11/3+12/3-22/3-1/3=

$$1 \frac { 1 } { 3 } + 1 \frac { 2 } { 3 } - 2 \frac { 2 } { 3 } - \frac { 1 } { 3 } =$$

Evaluate

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Solution Steps

Multiply 1 and 3 to get 3.

$$\frac{3+1}{3}+\frac{1\times 3+2}{3}-\frac{2\times 3+2}{3}-\frac{1}{3}$$

Add 3 and 1 to get 4.

$$\frac{4}{3}+\frac{1\times 3+2}{3}-\frac{2\times 3+2}{3}-\frac{1}{3}$$

Multiply 1 and 3 to get 3.

$$\frac{4}{3}+\frac{3+2}{3}-\frac{2\times 3+2}{3}-\frac{1}{3}$$

Add 3 and 2 to get 5.

$$\frac{4}{3}+\frac{5}{3}-\frac{2\times 3+2}{3}-\frac{1}{3}$$

Since \frac{4}{3} and \frac{5}{3} have the same denominator, add them by adding their numerators.

$$\frac{4+5}{3}-\frac{2\times 3+2}{3}-\frac{1}{3}$$

Add 4 and 5 to get 9.

$$\frac{9}{3}-\frac{2\times 3+2}{3}-\frac{1}{3}$$

Divide 9 by 3 to get 3.

$$3-\frac{2\times 3+2}{3}-\frac{1}{3}$$

Multiply 2 and 3 to get 6.

$$3-\frac{6+2}{3}-\frac{1}{3}$$

Add 6 and 2 to get 8.

$$3-\frac{8}{3}-\frac{1}{3}$$

Convert 3 to fraction \frac{9}{3}.

$$\frac{9}{3}-\frac{8}{3}-\frac{1}{3}$$

Since \frac{9}{3} and \frac{8}{3} have the same denominator, subtract them by subtracting their numerators.

$$\frac{9-8}{3}-\frac{1}{3}$$

Subtract 8 from 9 to get 1.

$$\frac{1}{3}-\frac{1}{3}$$

Subtract \frac{1}{3} from \frac{1}{3} to get 0.

$$0$$

Factor

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