Solve for c
c = \frac{49}{10} = 4\frac{9}{10} = 4.9
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5\left(1\times 2+1\right)=10c-2\left(3\times 5+2\right)
Multiply both sides of the equation by 10, the least common multiple of 2,5.
5\left(2+1\right)=10c-2\left(3\times 5+2\right)
Multiply 1 and 2 to get 2.
5\times 3=10c-2\left(3\times 5+2\right)
Add 2 and 1 to get 3.
15=10c-2\left(3\times 5+2\right)
Multiply 5 and 3 to get 15.
15=10c-2\left(15+2\right)
Multiply 3 and 5 to get 15.
15=10c-2\times 17
Add 15 and 2 to get 17.
15=10c-34
Multiply -2 and 17 to get -34.
10c-34=15
Swap sides so that all variable terms are on the left hand side.
10c=15+34
Add 34 to both sides.
10c=49
Add 15 and 34 to get 49.
c=\frac{49}{10}
Divide both sides by 10.
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