Solve 11/2+3/6-4/6=52/6=5frac{1}{3}

$$1 \frac { 1 } { 2 } + \frac { 3 } { 6 } - \frac { 4 } { 6 } = 5 \frac { 2 } { 6 } = 5 \frac { 1 } { 3 }$$

Verify

Solution Steps

Multiply 1 and 2 to get 2.

$$\frac{2+1}{2}+\frac{3}{6}-\frac{4}{6}=\frac{5\times 6+2}{6}\text{ and }\frac{5\times 6+2}{6}=\frac{5\times 3+1}{3}$$

Add 2 and 1 to get 3.

$$\frac{3}{2}+\frac{3}{6}-\frac{4}{6}=\frac{5\times 6+2}{6}\text{ and }\frac{5\times 6+2}{6}=\frac{5\times 3+1}{3}$$

Reduce the fraction \frac{3}{6} to lowest terms by extracting and canceling out 3.

$$\frac{3}{2}+\frac{1}{2}-\frac{4}{6}=\frac{5\times 6+2}{6}\text{ and }\frac{5\times 6+2}{6}=\frac{5\times 3+1}{3}$$

Since \frac{3}{2} and \frac{1}{2} have the same denominator, add them by adding their numerators.

$$\frac{3+1}{2}-\frac{4}{6}=\frac{5\times 6+2}{6}\text{ and }\frac{5\times 6+2}{6}=\frac{5\times 3+1}{3}$$

Add 3 and 1 to get 4.

$$\frac{4}{2}-\frac{4}{6}=\frac{5\times 6+2}{6}\text{ and }\frac{5\times 6+2}{6}=\frac{5\times 3+1}{3}$$

Divide 4 by 2 to get 2.

$$2-\frac{4}{6}=\frac{5\times 6+2}{6}\text{ and }\frac{5\times 6+2}{6}=\frac{5\times 3+1}{3}$$

Reduce the fraction \frac{4}{6} to lowest terms by extracting and canceling out 2.

$$2-\frac{2}{3}=\frac{5\times 6+2}{6}\text{ and }\frac{5\times 6+2}{6}=\frac{5\times 3+1}{3}$$

Convert 2 to fraction \frac{6}{3}.

$$\frac{6}{3}-\frac{2}{3}=\frac{5\times 6+2}{6}\text{ and }\frac{5\times 6+2}{6}=\frac{5\times 3+1}{3}$$

Since \frac{6}{3} and \frac{2}{3} have the same denominator, subtract them by subtracting their numerators.

$$\frac{6-2}{3}=\frac{5\times 6+2}{6}\text{ and }\frac{5\times 6+2}{6}=\frac{5\times 3+1}{3}$$

Subtract 2 from 6 to get 4.

$$\frac{4}{3}=\frac{5\times 6+2}{6}\text{ and }\frac{5\times 6+2}{6}=\frac{5\times 3+1}{3}$$

Multiply 5 and 6 to get 30.

$$\frac{4}{3}=\frac{30+2}{6}\text{ and }\frac{5\times 6+2}{6}=\frac{5\times 3+1}{3}$$

Add 30 and 2 to get 32.

$$\frac{4}{3}=\frac{32}{6}\text{ and }\frac{5\times 6+2}{6}=\frac{5\times 3+1}{3}$$

Reduce the fraction \frac{32}{6} to lowest terms by extracting and canceling out 2.

$$\frac{4}{3}=\frac{16}{3}\text{ and }\frac{5\times 6+2}{6}=\frac{5\times 3+1}{3}$$

Compare \frac{4}{3} and \frac{16}{3}.

$$\text{false}\text{ and }\frac{5\times 6+2}{6}=\frac{5\times 3+1}{3}$$

Multiply 5 and 6 to get 30.

$$\text{false}\text{ and }\frac{30+2}{6}=\frac{5\times 3+1}{3}$$

Add 30 and 2 to get 32.

$$\text{false}\text{ and }\frac{32}{6}=\frac{5\times 3+1}{3}$$

Reduce the fraction \frac{32}{6} to lowest terms by extracting and canceling out 2.

$$\text{false}\text{ and }\frac{16}{3}=\frac{5\times 3+1}{3}$$

Multiply 5 and 3 to get 15.

$$\text{false}\text{ and }\frac{16}{3}=\frac{15+1}{3}$$

Add 15 and 1 to get 16.

$$\text{false}\text{ and }\frac{16}{3}=\frac{16}{3}$$

Compare \frac{16}{3} and \frac{16}{3}.

$$\text{false}\text{ and }\text{true}$$

The conjunction of \text{false} and \text{true} is \text{false}.

$$\text{false}$$