Solve 1div[32*(1-5/8)+1/2]

$$1 \div [ 32 \times ( 1 - \frac { 5 } { 8 } ) + \frac { 1 } { 2 } ]$$

Evaluate

$$\frac{2}{25}=0.08$$

Solution Steps

Convert 1 to fraction \frac{8}{8}.

$$\frac{1}{32\left(\frac{8}{8}-\frac{5}{8}\right)+\frac{1}{2}}$$

Since \frac{8}{8} and \frac{5}{8} have the same denominator, subtract them by subtracting their numerators.

$$\frac{1}{32\times \frac{8-5}{8}+\frac{1}{2}}$$

Subtract 5 from 8 to get 3.

$$\frac{1}{32\times \frac{3}{8}+\frac{1}{2}}$$

Express 32\times \frac{3}{8} as a single fraction.

$$\frac{1}{\frac{32\times 3}{8}+\frac{1}{2}}$$

Multiply 32 and 3 to get 96.

$$\frac{1}{\frac{96}{8}+\frac{1}{2}}$$

Divide 96 by 8 to get 12.

$$\frac{1}{12+\frac{1}{2}}$$

Convert 12 to fraction \frac{24}{2}.

$$\frac{1}{\frac{24}{2}+\frac{1}{2}}$$

Since \frac{24}{2} and \frac{1}{2} have the same denominator, add them by adding their numerators.

$$\frac{1}{\frac{24+1}{2}}$$

Add 24 and 1 to get 25.

$$\frac{1}{\frac{25}{2}}$$

Divide 1 by \frac{25}{2} by multiplying 1 by the reciprocal of \frac{25}{2}.

$$1\times \frac{2}{25}$$

Multiply 1 and \frac{2}{25} to get \frac{2}{25}.

$$\frac{2}{25}$$

Factor

$$\frac{2}{5 ^ {2}} = 0.08$$