Solve 1div0.75+1div10

$$1 \div 0.75+1 \div 10$$

Evaluate

$$\frac{43}{30}\approx 1.433333333$$

Solution Steps

Expand \frac{1}{0.75} by multiplying both numerator and the denominator by 100.

$$\frac{100}{75}+\frac{1}{10}$$

Reduce the fraction \frac{100}{75} to lowest terms by extracting and canceling out 25.

$$\frac{4}{3}+\frac{1}{10}$$

Least common multiple of 3 and 10 is 30. Convert \frac{4}{3} and \frac{1}{10} to fractions with denominator 30.

$$\frac{40}{30}+\frac{3}{30}$$

Since \frac{40}{30} and \frac{3}{30} have the same denominator, add them by adding their numerators.

$$\frac{40+3}{30}$$

Add 40 and 3 to get 43.

$$\frac{43}{30}$$

Factor

$$\frac{43}{2 \cdot 3 \cdot 5} = 1\frac{13}{30} = 1.4333333333333333$$