Solve 1*f(x)=-4/x-2

$$1 \cdot f ( x ) = \frac { - 4 } { x - 2 }$$

Solve for f

$$f=-\frac{4}{x\left(x-2\right)}$$

$$x\neq 2\text{ and }x\neq 0$$

Steps for Solving Linear Equation

Multiply both sides of the equation by x-2.

$$1fx\left(x-2\right)=-4$$

Use the distributive property to multiply 1fx by x-2.

$$fx^{2}-2fx=-4$$

Combine all terms containing f.

$$\left(x^{2}-2x\right)f=-4$$

Divide both sides by x^{2}-2x.

$$\frac{\left(x^{2}-2x\right)f}{x^{2}-2x}=-\frac{4}{x^{2}-2x}$$

Dividing by x^{2}-2x undoes the multiplication by x^{2}-2x.

$$f=-\frac{4}{x^{2}-2x}$$

Divide -4 by x^{2}-2x.

$$f=-\frac{4}{x\left(x-2\right)}$$

Solve for x (complex solution)

$$x=\frac{\sqrt{f\left(f-4\right)}+f}{f}$$

$$x=\frac{-\sqrt{f\left(f-4\right)}+f}{f}\text{, }f\neq 0$$

Solve for x

$$x=\frac{\sqrt{f\left(f-4\right)}+f}{f}$$

$$x=\frac{-\sqrt{f\left(f-4\right)}+f}{f}\text{, }f<0\text{ or }f\geq 4$$