Solve 1*2^3+1*2^2+0*2^1+1*2^0

$$1 \cdot 2 ^ { 3 } + 1 \cdot 2 ^ { 2 } + 0 \cdot 2 ^ { 1 } + 1 \cdot 2 ^ { 0 }$$

Evaluate

$$13$$

Solution Steps

Calculate 2 to the power of 3 and get 8.

$$1\times 8+1\times 2^{2}+0\times 2^{1}+1\times 2^{0}$$

Multiply 1 and 8 to get 8.

$$8+1\times 2^{2}+0\times 2^{1}+1\times 2^{0}$$

Calculate 2 to the power of 2 and get 4.

$$8+1\times 4+0\times 2^{1}+1\times 2^{0}$$

Multiply 1 and 4 to get 4.

$$8+4+0\times 2^{1}+1\times 2^{0}$$

Add 8 and 4 to get 12.

$$12+0\times 2^{1}+1\times 2^{0}$$

Calculate 2 to the power of 1 and get 2.

$$12+0\times 2+1\times 2^{0}$$

Multiply 0 and 2 to get 0.

$$12+0+1\times 2^{0}$$

Add 12 and 0 to get 12.

$$12+1\times 2^{0}$$

Calculate 2 to the power of 0 and get 1.

$$12+1\times 1$$

Multiply 1 and 1 to get 1.

$$12+1$$

Add 12 and 1 to get 13.

$$13$$

Factor

$$13$$