Solve 1^2pi/3+cos^43pi/2-tan^2pi/3

$$1 ^ { 2 } \frac { \pi } { 3 } + \cos ^ { 4 } \frac { 3 \pi } { 2 } - \tan ^ { 2 } \frac { \pi } { 3 }$$

Evaluate

$$\frac{\pi }{3}-3\approx -1.952802449$$

Short Solution Steps

Calculate 1 to the power of 2 and get 1.

$$1\times \frac{\pi }{3}+\left(\cos(\frac{3\pi }{2})\right)^{4}-\left(\tan(\frac{\pi }{3})\right)^{2}$$

Express 1\times \frac{\pi }{3} as a single fraction.

$$\frac{\pi }{3}+\left(\cos(\frac{3\pi }{2})\right)^{4}-\left(\tan(\frac{\pi }{3})\right)^{2}$$

Get the value of \cos(\frac{3\pi }{2}) from trigonometric values table.

$$\frac{\pi }{3}+0^{4}-\left(\tan(\frac{\pi }{3})\right)^{2}$$

Calculate 0 to the power of 4 and get 0.

$$\frac{\pi }{3}+0-\left(\tan(\frac{\pi }{3})\right)^{2}$$

Anything plus zero gives itself.

$$\frac{\pi }{3}-\left(\tan(\frac{\pi }{3})\right)^{2}$$

Get the value of \tan(\frac{\pi }{3}) from trigonometric values table.

$$\frac{\pi }{3}-\left(\sqrt{3}\right)^{2}$$

The square of \sqrt{3} is 3.

$$\frac{\pi }{3}-3$$

To add or subtract expressions, expand them to make their denominators the same. Multiply 3 times \frac{3}{3}.

$$\frac{\pi }{3}-\frac{3\times 3}{3}$$

Since \frac{\pi }{3} and \frac{3\times 3}{3} have the same denominator, subtract them by subtracting their numerators.

$$\frac{\pi -3\times 3}{3}$$

Do the multiplications in \pi -3\times 3.

$$\frac{\pi -9}{3}$$

Factor

$$\frac{\pi - 9}{3} = -1.9528024488034024$$